4. Linear Equation In Two Variables Mathematics Exercise - 4.1 class 9 Maths in English - CBSE Study
NCERT Solutions for Class 9 Mathematics are carefully prepared according to the latest CBSE syllabus and NCERT textbooks to help students understand every concept clearly. These solutions cover all important 4. Linear Equation In Two Variables with detailed explanations and step-by-step answers for better exam preparation. Each Exercise 4.1 is explained in simple language so that students can easily grasp the fundamentals and improve their academic performance. The study material is designed to support daily homework, revision practice, and final exam preparation for Class 9 students. With accurate answers, concept clarity, and structured content, these NCERT solutions help learners build confidence and score higher marks in their examinations. Whether you are revising a specific topic or preparing an entire chapter, this resource provides reliable and syllabus-based guidance for complete success in Mathematics.
Class 9 English Medium Mathematics All Chapters:
4. Linear Equation In Two Variables
1. Exercise 4.1
Chapter 4. Linear Equation In Two Variables
Exercise 4.1
1. The cost of a notebook is twice the cost of a pen. Write a linear equation in two variables to represent this statement.
(Take the cost of a notebook to be 'x' and that of a pen to be 'y' )
Solution:
Let the cost of pen = y
Let the cost of notebook= x
Then, According To Question,
x = 2y
⇒ x - 2y = 0
2. Express the following linear equations in the form ax + by + c = 0 and indicate the values of a, b and c in each case:
(i) 2x + 3y = 9.35
Solution:
(i) 2x + 3y = 9.35
Expressing the equation in the form of ax + by + c = 0,
∴ 2x+3y-9.35= 0
On Comparing, We have
Then, a= 2, b= 3, c= -9.3
(ii) x – 5y – 10 = 0
Solution:
(ii) x – 5y – 10 = 0
Expressing the equation in the form of ax + by + c = 0,
∴ x- 5y - 10 = 0
On Comparing, We have
Then, a= 1, b= -5, c= -10
(iii) –2x + 3y = 6
Solution:
(iii) –2x + 3y = 6
Expressing the equation in the form of ax + by + c = 0,
∴ -2x + 3y - 6= 0
On Comparing, We have
Then, a= -2, b= 3, c= -6
(iv) x = 3y
Solution:
(iv) x = 3y
Expressing the equation in the form of ax + by + c = 0,
∴ x - 3y= 0
On Comparing, We have
Then, a= 1, b= -3, c= 0
(v) 2x = –5y
Solution:
(v) 2x = –5y
Expressing the equation in the form of ax + by + c = 0,
∴ 2x + 5y= 0
On Comparing, We have
Then, a= 2, b= 5, c= 0
(vi) 3x + 2 = 0
Solution:
(vi) 3x + 2 = 0
Expressing the equation in the form of ax + by + c = 0,
∴ 3x + 2= 0
On Comparing, We have
Then, a= 3, b= 0, c= 2
(vii) y – 2 = 0
Solution:
(vii) y – 2 = 0
Expressing the equation in the form of ax + by + c = 0,
∴ y-2= 0
On Comparing, We have
Then, a= 0, b= 1, c= -2
(viii) 5 = 2x
Solution:
(viii) 5 = 2x
Expressing the equation in the form of ax + by + c = 0,
∴ 2x - 5= 0
On Comparing, We have
Then, a= 2, b= 0, c= -5
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