Introduction to Linear Polynomials Class 9 Mathematics Ganita Manjari [LATEST] Solutions Exercise Set 2.6 in English - CBSE Study
NCERT Solutions for Class 9 Mathematics Ganita Manjari are carefully prepared according to the latest CBSE syllabus and NCERT textbooks to help students understand every concept clearly. These solutions cover all important Introduction to Linear Polynomials with detailed explanations and step-by-step answers for better exam preparation. Each Exercise Set 2.6 is explained in simple language so that students can easily grasp the fundamentals and improve their academic performance. The study material is designed to support daily homework, revision practice, and final exam preparation for Class 9 students. With accurate answers, concept clarity, and structured content, these NCERT solutions help learners build confidence and score higher marks in their examinations. Whether you are revising a specific topic or preparing an entire chapter, this resource provides reliable and syllabus-based guidance for complete success in Mathematics Ganita Manjari.
Class 9 English Medium Mathematics Ganita Manjari All Chapters:
Introduction to Linear Polynomials
6. Exercise Set 2.6
Exercise Set 2.6
Q1. Draw the graphs of the following sets of lines. In each case, reflect on the role of ‘a’ and ‘b’.
Solution:
The general form of a linear equation is:
y = ax + b
where,
a = slope of the line
b = y-intercept
(i) y = 4x, y = 2x, y = x
Here,
a = 4, 2, 1
b = 0 in all cases
Observation:
As the value of a increases, the line becomes steeper.
Since b = 0, all lines pass through the origin (0, 0).
(ii) y = –6x, y = –3x, y = –x
Here,
a = –6, –3, –1
b = 0 in all cases
Observation:
Negative values of a give downward sloping lines.
Greater negative value means steeper downward slope.
Since b = 0, all lines pass through the origin.
(iii) y = 5x, y = –5x
Here,
a = 5 and –5
b = 0
Observation:
Positive a gives an upward sloping line.
Negative a gives a downward sloping line.
Both lines pass through the origin because b = 0.
(iv) y = 3x – 1, y = 3x, y = 3x + 1
Here,
a = 3 in all cases
b = –1, 0, 1
Observation:
All lines have the same slope, so they are parallel.
Changing b shifts the line upward or downward.
b determines where the line cuts the y-axis.
(v) y = –2x – 3, y = –2x, y = –2x + 3
Here,
a = –2 in all cases
b = –3, 0, 3
Observation:
All lines have the same negative slope, so they are parallel.
Changing b changes the y-intercept.
Negative b shifts the line downward and positive b shifts it upward.
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