2. Whole Numbers Mathematics Exercise - 2.3 class 6 Maths in English - CBSE Study
NCERT Solutions for Class 6 Mathematics are carefully prepared according to the latest CBSE syllabus and NCERT textbooks to help students understand every concept clearly. These solutions cover all important 2. Whole Numbers with detailed explanations and step-by-step answers for better exam preparation. Each Exercise 2.3 is explained in simple language so that students can easily grasp the fundamentals and improve their academic performance. The study material is designed to support daily homework, revision practice, and final exam preparation for Class 6 students. With accurate answers, concept clarity, and structured content, these NCERT solutions help learners build confidence and score higher marks in their examinations. Whether you are revising a specific topic or preparing an entire chapter, this resource provides reliable and syllabus-based guidance for complete success in Mathematics.
Class 6 English Medium Mathematics All Chapters:
2. Whole Numbers
3. Exercise 2.3
Exercise-2.3
Q1. Which of the following will not represent zero:
(a) 1 + 0 (b) 0 × 0 (c) 0/2 (d) 10 -10/2
Solution:
(a) 1 + 0 = 1
So, it is not represent zero
(b) 0 × 0 = 0
it is represent zero
(c) 0/2 = 0
it is represent zero
Q2. If the product of two whole numbers is zero, can we say that one or both of them will be zero? Justify through examples.
Solution:
Yes, we know that the product of any whole numbers with zero is always zero.
Q3. If the product of two whole numbers is 1, can we say that one or both of them will be 1? Justify through examples.
Solution:
If only one number be 1 then the product cannot be 1.
Examples:
Here we see that one of two is 1 then product will be always second number.
If both numbers are 1, then the product is 1
Q4. Find using distributive property :
(a) 728 × 101 (b) 5437 × 1001 (c) 824 × 25 (d) 4275 × 125 (e) 504 × 35
Solution:
(a) 728 × 101
= 728(100 + 1)
= 728 × 100 + 728 × 1
= 72800 + 728
= 73528
Solution:
(b) 5437 × 1001
= 5437(1000 + 1)
= 5437 × 1000 + 5437 × 1
= 5437000 + 5437
= 5442437
Solution:
(c) 824 × 25
= 824(20 + 5)
= 824 × 20 + 824 × 5
= 16480 + 4120
= 20600
Solution:
(d) 4275 × 125
= 4275(100 + 20 + 5)
= 4275 × 100 + 4275 × 20 + 4275 × 5
= 427500 + 85500 + 21375
= 534375
Solution:
(e) 504 × 35
= (500 + 4) × 35
= 500 × 35 + 4 × 35
= 17500 + 140
= 17640
Q5. Study the pattern :
1 × 8 + 1 = 9 1234 × 8 + 4 = 9876
12 × 8 + 2 = 98 12345 × 8 + 5 = 98765
123 × 8 + 3 = 987
Write the next two steps. Can you say how the pattern works?
(Hint: 12345 = 11111 + 1111 + 111 + 11 + 1).
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